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13x^2=26x^2
We move all terms to the left:
13x^2-(26x^2)=0
We add all the numbers together, and all the variables
-13x^2=0
a = -13; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-13)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-26}=0$
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